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Answer:
:. a=3,b=-6
Step-by-step explanation:
basic point:If a, b are the roots of an eqn, then (x-a)(x-b)=0be that quadratic equation.
If x=2/m, x=-3 are roots, then the eqn will be
(x-2/m)(x-(-3)=0
=>(x-2/3)(x+3)=0
=>x2-(2/3)x+3x-2=0
=>3x2-2x+9x-6=0
=>3x2+7*-6=0 is the required eqn
Compare the eqn with ax2+7x+b=0
Therefore, a =3,b=-6
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