Question

anwser question 1 and 2

Answer 1

1
$\sqrt [4] {( { \frac{132}{143}) }^{ - 2} } \\ = \sqrt[4]{ {( \frac{143}{132}) }^{2} } \\ = \sqrt{ \frac{143}{132} } \\ \sqrt{\frac{13}{12}}$
2
$6 - x - {x}^{2} = 0 \\ - {x}^{2} - x + 6 = 0 \\ {x}^{2} + x - 6 = 0\\ {x}^{2} + 3x - 2x - 6 = 0 \\ x(x + 3) - 2(x + 3) = 0 \\ (x - 2)(x + 3)$
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Answer 2

6-x-x^2
=-[ x^2+x-6]
= - (x+3 ) ( x-2)