any 2 persons help me i want to mark as brainliest
Q.a. A lot of 20 bulbs contain 5 defective bulbs 1 bulb is drawn at random from the lot What is the probability that it is defective
b.Suppose the bulb drawn in
is not defective and is not replaced Now 1 bulb is drawn at random from the rest What is the probability that this bulb is a defective b. not defective.
Answers
Answered by
0
Answer:
(a) 1/4 (b) 5/19, 14/19
Step-by-step explanation:
Question a:
Total number of bulbs = 20
Total number of defective bulbs = 5
P(defective bulb) = 5/20 = 1/4
Question b:
1 good bulb has been removed
Total number of bulb = 20 - 1 = 19
Total number of defective bulbs = 5
Total number of not defective bulbs = 19 - 5 = 14
P(defective bulb) = 5/19
P(non defective bulbs = 14/19
Answer: (a) 1/4 (b) 5/19, 14/19
Anonymous:
iam sorry ur answer was right sorry i reported
Answered by
0
Total numbers of bulbs = 20
Numbers of defective bulbs = 4
Probability of getting a defective bulb = 4/20 = 1/5
(ii) One non defective bulb is drawn in (i) then the total numbers of bulb left is 19
Total numbers of events = 19
Favourable numbers of events = 19 - 4 = 15
Probability that the bulb is not defective = 15/19
Hey here's your answer✔️
plz plz plz mark it as brainliest✌️
Numbers of defective bulbs = 4
Probability of getting a defective bulb = 4/20 = 1/5
(ii) One non defective bulb is drawn in (i) then the total numbers of bulb left is 19
Total numbers of events = 19
Favourable numbers of events = 19 - 4 = 15
Probability that the bulb is not defective = 15/19
Hey here's your answer✔️
plz plz plz mark it as brainliest✌️
but darshan i think that may be this 1 maybe the answer
1. 1/4
2. 14/19
a. 4/19
b. 15/19
is it
"Suppose the bulb drawn in is not defective" .... the one that is removed is not defective. Here, the answer presented as the bulb that was removed is defective. This is incorrect.
may be the bulb was defective
It is stated in the question ...."Suppose the bulb drawn in is not defective"
ok so ur answer may be correct
Similar questions