Question

Any 5 consecutive numbers whose sum is 45

Answer 1

Step-by-step explanation:

Let the five consecutive no.s are=>

x,x+1,x+2,x+3,x+4

A.T.Q=>

=x+x+1+x+2+x+3+x+4=45

=5+10x=45

=10x=45-5

=10x=40

=x=40/10

=x=4

Thus, 5 consecutive no.S whose sum is 45 are as follows

4,5,6,7,8