Question

Any answers to these questions?

Answer 1

) area (ΔPRQ)=1/2 area(APQ)[since RQ is a median and median divides triangle into equal areas]

=area(ΔABC)=............(1)

area (ΔARC)=1/2 area(ΔAPC) [in the ΔACP , CR is the median]

=1/2*1/2 area(ΔABC) [since CP is the median of ABC]

=1/4*x=x/4 ............(2)

from (1) and (2) area(ΔPRQ)=1/2 area(ΔARC)

(ii)

area(ΔRQC)=1/2 area(ΔARC) [since RQ is the median of triangle ARC]

=1/2*1/2area(ΔAPC)=1/4*1/2 area(ΔABC)=1/8x

(iii)

area(ΔPBQ)=area(ΔPQC)[the triangle with same base and between same set of parallel lines ]

=1/2 area(ΔAPC) [since PQ is the median of triangle APC]

=1/2*1/2 area(ΔABC)

=1/4 area(ΔABC)=x/4

from (2) area (ΔARC)=x/4

hence area(ΔPBQ)=area(ΔARC)

Answer 2

Step-by-step explanation:

Given

AB||DC

AD||BC

PROVE THAT:-

angle DAB = angle DCB

NOW,

because

AB||DC

AD||BC

therefore , this is a parallelogram

we know that, In parallelogram

opposite angel are equal.

so hence proved

angel DAB = angel DCB