Question

any body answer this question plzz..

Answer 1

The acceleration-time graph is provided.

initial velocity(u) of the object was 0.

We need to find the final velocity(v).

Velocity will increase from t=0 second to t=12 second as the acceleration is positive.

after 12 second, velocity will start decreasing. So maximum velocity is attained at t= 12 second.
______________________________

We know that area under the acceleration-time graph gives the change in velocity.

it's a right angled triangle with base 12 second and height 10 m/s^2.

area = change in velocity

= 1/2 ×base × height

= 1/2 × 12 × 10

= 60 m/s

So final velocity will be given as:

v = u + change in velocity

=> v = 0 + 60

=> v = 60 m/s

Thus final velocity will be 60m/s which is maximum.

Answer 2

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The acceleration-time graph is provided.

initial velocity(u) of the object was 0.

We need to find the final velocity(v).

Velocity will increase from t=0 second to t=12 second as the acceleration is positive.

after 12 second, velocity will start decreasing. So maximum velocity is attained at t= 12 second.

______________________________

We know that area under the acceleration-time graph gives the change in velocity.

it's a right angled triangle with base 12 second and height 10 m/s^2.

area = change in velocity

= 1/2 ×base × height

= 1/2 × 12 × 10

= 60 m/s

So final velocity will be given as:

v = u + change in velocity

=> v = 0 + 60

=> v = 60 m/s

Thus final velocity will be 60m/s which is maximum.

HOPE SO IT WILL HELP......