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this is your answer please see this
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A ------ 5 m -------- B -------- 5m -------- C
Ma = 10 kg Mb = 20 kg Mc = 30 kg
Net gravitational force Fa on A is towards right side.
Fa = G Ma Mb / 5² + G Ma Mc / 10²
= 6.67 * 10⁻¹¹ * 10 [ 20/ 5² + 30 /1 00] N
= 7.34 * 10^-10 N
Net gravitational force Fc on C is towards B, left side and its magnitude is equal to Fa ie., 7.34 * 10^-10 N
Net gravitational force on B is Fb & is towards C
Fb = G Mb [ Mc - Ma ]/ 5²
= 6.67 * 10⁻¹¹ * 20 * 20 * 4 = 1.07 * 10^-7N
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