Math, asked by Shivamyadav4131, 1 year ago

any body can answer it

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Answers

Answered by sharmavijaylaxmi54

Answer:

Step-by-step explanation:

Lets take the LHS =

(cosA-sinA)+1/(cosA+sinA)-1

taking conjugate

(cosA-sinA)+1/(cosA+sinA)-1 × (cosA+sinA)+1/(cosA+sinA)+1

multiplying we get

=cos2A-sin2A+2cosA+1/2sinAcosA

=cos2A-sin2A+2cosA+sin2A+cos2A/2sinAcosA

on solving we get

=2cos2A+2cosA/2sinAcosA

=cosA+cos2A/sinAcosA

we can alsom write in the form of

cosA/sinAcosA +cos2A/sinAcosA

on solving we get

CosecA+cotA =R.H.S

I hope it helps you ^_^

Please mark as brainliest

Shivamyadav4131: i touches it by mistake i want to mark your

Shivamyadav4131: not other

sharmavijaylaxmi54: Ok

sharmavijaylaxmi54: Now I think you can mark

Shivamyadav4131: but i want any two member

Shivamyadav4131: to mark

sharmavijaylaxmi54: Ok

Shivamyadav4131: hli

Shivamyadav4131: hlo

sharmavijaylaxmi54: Hey

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