any body can prove 1=2 and this is a right question so prove
Answers
Answered by
8
hey friend here is the answer !!!!
let ,
a=b
=>a²=ab (multiply both sides by a )
=>a²-b²= ab-b² (subtracting b² both sides )
=> (a+b)(a-b)=b(a-b). (factor both sides)
=> (a+b)=b. (divide both sides by a-b )
=> a+a = a (substitute a for b)
=> 2a = a
=> 2=1. proved !!!
hope this helps !!
be happy and stay blessed my friend !!!
let ,
a=b
=>a²=ab (multiply both sides by a )
=>a²-b²= ab-b² (subtracting b² both sides )
=> (a+b)(a-b)=b(a-b). (factor both sides)
=> (a+b)=b. (divide both sides by a-b )
=> a+a = a (substitute a for b)
=> 2a = a
=> 2=1. proved !!!
hope this helps !!
be happy and stay blessed my friend !!!
Anonymous:
* a + b = b
Answered by
7
Answer :
1)
Let us assume,
x = 1
Now, multiplying both sides by x, we get
x² = x
Again, subtracting 1 from both sides, we get
x² - 1 = x - 1
⇒ (x + 1)(x - 1) = (x - 1)
⇒ x + 1 = 1
⇒ 1 + 1 = 1 [∵ x = 1]
⇒ 2 = 1
⇒ 1 = 2 [Proved]
WHERE DID U DO WRONG?
~ It is a certain that x = 1 ⇒ x - 1 = 0 but we ignored it while calculating.
Another method.
Let us take,
0 = 0
⇒ 1 - 1 = 1 - 1
⇒ 1.1 - 1.1 = 1² - 1²
⇒ 1(1 - 1) = (1 + 1)(1 - 1)
⇒ 1 = 1 + 1
⇒ 1 = 2 [Proved]
WHERE DID WE DO WRONG?
~ Although 1 - 1 = 0 and 0/0 is indeterminate form but we ignored it on purpose.
#MarkAsBrainliest
1)
Let us assume,
x = 1
Now, multiplying both sides by x, we get
x² = x
Again, subtracting 1 from both sides, we get
x² - 1 = x - 1
⇒ (x + 1)(x - 1) = (x - 1)
⇒ x + 1 = 1
⇒ 1 + 1 = 1 [∵ x = 1]
⇒ 2 = 1
⇒ 1 = 2 [Proved]
WHERE DID U DO WRONG?
~ It is a certain that x = 1 ⇒ x - 1 = 0 but we ignored it while calculating.
Another method.
Let us take,
0 = 0
⇒ 1 - 1 = 1 - 1
⇒ 1.1 - 1.1 = 1² - 1²
⇒ 1(1 - 1) = (1 + 1)(1 - 1)
⇒ 1 = 1 + 1
⇒ 1 = 2 [Proved]
WHERE DID WE DO WRONG?
~ Although 1 - 1 = 0 and 0/0 is indeterminate form but we ignored it on purpose.
#MarkAsBrainliest
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