any body please help me in math
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Given -
- ABC and ADC are two right triangles with common hypotenuse AC.
To Prove -
- ∠CAD = ∠CBD.
Given -
- ABC and ADC are two right triangles with common hypotenuse AC.
Proof -
∵ AC is the common hypotenuse, ABC and ADC are two right triangles.
∴ ∠ABC = 90° = ∠ADC
⇒ Both the triangles are in the same semicircle.
∴ Points A, B, D and C are concyclic.
∵ DC is a chord
∴ ∠CAD = ∠CBD.
∵ Angles in the same segment are equal.
Once again hope it helps uh parth...hehe ❤︎
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Pratham bhaiya Aliza.didi ek answer me itna sara thanks kaise de di
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