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First write the balanced chemical reaction
N2 + 3H2 ------> 2NH3
(14×2)g + 3(1×2) -------> 2(17)g
50kg. + 10kg -------> ?
according to the balanced chemical reaction 14×2g N2 requires 3(1×2)g of H2 to produce 2(17) g of NH3. So
then 10kg of H2 requires x kg of N2
x = 14×2×10/3(1×2)
x = 280/6
x = 46.6 kg
so 10kg requires 46.6 g of N2 but N2 is higher amount i.e 50kg
so N2 is excess then H2 becomes limiting reagent.
3(1×2)g. -----> 2(17)g
10000g -------> ?
= x = 10000×34/6
x = 340000/6
x = 56666.67 g NH3 produced
N2 + 3H2 ------> 2NH3
(14×2)g + 3(1×2) -------> 2(17)g
50kg. + 10kg -------> ?
according to the balanced chemical reaction 14×2g N2 requires 3(1×2)g of H2 to produce 2(17) g of NH3. So
then 10kg of H2 requires x kg of N2
x = 14×2×10/3(1×2)
x = 280/6
x = 46.6 kg
so 10kg requires 46.6 g of N2 but N2 is higher amount i.e 50kg
so N2 is excess then H2 becomes limiting reagent.
3(1×2)g. -----> 2(17)g
10000g -------> ?
= x = 10000×34/6
x = 340000/6
x = 56666.67 g NH3 produced
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