Question

any brainly challenger can solve

Answer 1

In the triangles ΔABD and ΔACD,

∠DAB=∠DAC.........(∵ AX bisects ∠CAB)

∠BDA=∠CDA.........(∵ AX bisects ∠CDA)

DA=DA.....................(common side)

∴By ASA congruence,

ΔABD≅ΔACD

Answer 2

This is the answer to your question