Any expert plz... solve full solution
If (0.2)x = 2 and log 2 = 0.3010, then the value of x to the nearest tenth is:
(a) -10.0,
(b) -0.5,
(c) -0.4,
(d) -0.2,
(e) 10.0
Answers
Answered by
0
0.2x = 2
log 0.2x = log 2
x log 0.2 = 0.301
x = 0.301/log 0.2
x = -0.43063364398
To the nearest tenth, x = -0.4
log 0.2x = log 2
x log 0.2 = 0.301
x = 0.301/log 0.2
x = -0.43063364398
To the nearest tenth, x = -0.4
Answered by
3
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✌️_______UR ANSWER_______✌️
(0.2)x = 2.
Taking log on both sides
log (0.2)x = log 2.
x log (0.2) = 0.3010, [since log 2 = 0.3010].
x log (2/10) = 0.3010.
x [log 2 - log 10] = 0.3010.
x [log 2 - 1] = 0.3010,[since log 10=1].
x [0.3010 -1] = 0.3010, [since log 2 = 0.3010].
x[-0.699] = 0.3010.
x = 0.3010/-0.699.
x = -0.4306….
x = -0.4 (nearest tenth)
Answer: (C)
⤴️_____HOPE HELP YOU_____⤴️
✌️_______UR ANSWER_______✌️
(0.2)x = 2.
Taking log on both sides
log (0.2)x = log 2.
x log (0.2) = 0.3010, [since log 2 = 0.3010].
x log (2/10) = 0.3010.
x [log 2 - log 10] = 0.3010.
x [log 2 - 1] = 0.3010,[since log 10=1].
x [0.3010 -1] = 0.3010, [since log 2 = 0.3010].
x[-0.699] = 0.3010.
x = 0.3010/-0.699.
x = -0.4306….
x = -0.4 (nearest tenth)
Answer: (C)
⤴️_____HOPE HELP YOU_____⤴️
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