Math, asked by Anonymous, 1 year ago

ANY GENIUS HERE??
plz solve it

A well with internal diameter of 12m is dug.It ïs 15m deep.The earth taken out of it is spread all around it to a width of 3m to form an embankment.Find the height of embankment....

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Answers

Answered by Anonymous
106

\textsf{Hey !!..}

The answer goes here....

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》To find -

Height of embankment.

》Given -

Internal radius, r = 6\:m

Height, h = 15\:m

Width, w = 3\:m

》Solution -

The internal radius given is 6 m. So the external radius will be equal to the sum of the internal radius and the width.

i.e.,

External radius, R = 6+3=9\:m

Now, let us assume that the height of the embankment is H.

So, the volume of the well will be equal to volume of embankment.

\pi{r}^{2}h = \pi (R^{2}-r^{2})h

\frac{22}{7}\times {6}^{2}\times 15 = \frac{22}{7}\times (9^{2}-6^{2})\times 15

36\times 15 = 45\times H

H = 12

So, the height of the embankment is 12 m.

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\textsf{Thanks !!..}


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Answered by BrainlyVirat
71
❤️Here's the answer :) !❤️

Q.) A well with internal diameter of 12m is dug. It ïs 15m deep. The earth taken out of it is spread all around it to a width of 3m to form an embankment. Find the height of embankment.

Step-by-step explanation :-

Given :-

Radius of the well => 6 metres ( 12/2 )

Height => 15 metres

Solution :-

Now,

Let's find the volume of the earth taken out of the well

 \sf{ = \pi \: r {}^{2} h}

 \sf{ = \frac{22}{7} \times 6 {}^{2} \times 15} <br />

 \sf{ = \frac{22}{7} \times 36 \times 15}

 \sf{ = \frac{11880}{7}}

 \sf{ = 1697.14} \: m {}^{3}

Now,

The outer width ( radius ) of the embankment

= ( r1 ) = ( 6 + 3 ) = 9 metres

Hence,

Area of the embankment = Outer area - Interior area

 \sf{ \ = ( \pi \: r1 ) {}^{2} -( \pi \: r) {}^{2} }

 \sf{ = \frac{22}{7} \times (9 {}^{2} - 6 {}^{2})}

 \sf{ = \frac{22}{7} \times (81 - 36)}

 \sf{ = \frac{22}{7} \times 45}

 \sf{ = \frac{990}{7}}

 \sf{ = 141.42} \: m {}^{2}
Hence,

Area of the embankment is 141.42 metre sq.

Now,

As per your question ,

We have to find the Height of the embankment

Hence,

Height of the embankment =  \sf{ = \frac{Volume}{Area} }

 \sf{ = \frac{1697.14}{141.42} }

 \sf{ = 12 \: metre}


Hence,

Height of the embankment is 12 metre.

________________________________

Thank you !

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