Math, asked by jattjssinghaulakh, 1 year ago

ANY GENIUS here who can solve it........

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amritsarigirl: what i should do monday is my test
amritsarigirl: 8 chapter
jattjssinghaulakh: # तुम एक बार बिना देखे sare sums ki practice कर कर देखो
amritsarigirl: hor ki kra
amritsarigirl: time table ik din vich kistara kra
jattjssinghaulakh: aur haan रटआ mat lagana/ cramp mat karna Samajh Kar karna
siddhartharao77: Practice makes u perfect. Even ur teachers will say the same.. Please don't disturb others here.!
jattjssinghaulakh: okay bro
amritsarigirl: time table
amritsarigirl: 8 ch ki konsa ch kis time krna hai

Answers

Answered by siddhartharao77
5

Given, SI = 800, Time n = 2 years.

We know that SI = PTR/100

⇒ 800 = (P * 2 * R)/100

⇒ 80000 = 2PR

⇒ PR = 40000    ------ (1)



Given, SI = 820, Time n = 2 years.

We know that CI = P(1 + R/100)^T - P

⇒ P(1 + R/100)^2 - P

⇒ P[(1 + R/100)^2 - 1]

⇒ P[2R/100 + R^2/10000]

⇒ 2PR/100 + PR^2/10000

⇒ (2 * 40000)/100 + (40000 * R)/10000

⇒ 800 + 4R


Given Compound interest = 820

⇒ 820 = 800 + 4R

⇒ 820 - 800 = 4R

⇒ 20 = 4R

⇒ R = 5%.



Substitute r = 5% in (1), we get

⇒ PR = 40000

⇒ P = 40000/5

⇒ P = 8000.


Therefore, the sum = 8000 and rate of interest = 5%.


Hope it helps!


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