Question

any genius out here?
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Answer 1

anneyong :)

$\frac{( \sqrt{x + 1} ) + ( \sqrt{x - 1)} }{ \sqrt{x + 1} - \sqrt{x - 1} } = \frac{2}{1} \\ \\ \frac{( \sqrt{x + 1)} + ( \sqrt{x - 1)} + ( \sqrt{x + 1)} - ( \sqrt{x - 1)} }{ \sqrt{x + 1} + \sqrt{x - 1} - \sqrt{x + 1} + \sqrt{x - 1} } = \frac{2 + 1}{2 - 1} \\ \\ = \frac{ \sqrt{x + 1} }{ \sqrt{x - 1} } = 3 \\ \\ = > \frac{x + 1}{x - 1} = 9 \\ \\ = > 9x - 9 = x + 1 \\ \\ = > 8x = 10$

so,

the the value of x is 5/4

#SuJu ;)

Answer 2

Here is ur ans...

value of x is 5/4