any genius plz solve the problems ☺☺☺☺☺☺ But need.. urgent
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(37)
3√5x² +25x +10√5= 0.
3√5x² +15x + 10x +10√5= 0.
3x(√5x + 5) + 2√5(√5x + 5)= 0
(3x +2√5) (√5x + 5) = 0
(3x +2√5) = 0 or (√5x + 5) = 0
3x = -2√5 or √5x = -5
x = -2√5/3 or x = -5/ √5= -5×√5/√5×√5= -5√5/5= -√5 [by rationalising the denominator]
Hence, roots of equation 3√5x² +25x +10√5= 0 are -2√5/3 and -√5.
(38)
√3x²-2√2x-2√3=0
√3x²-3√2x+√2x=0
√3(x-√6)+√2(x-√6)=0
(√3+√2)(x-√6)=0
=>(√3x+√2)=0. OR. (x-√6)=0
=x=-√2/√3. OR. x=√6
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