Question

any help would be appreciated please help​

Answer 1

Explanation:

Given,

A network resistor is connected to 16V battery with terminal resistance 1Ω

i) The resistor are connected in parallel across AB,

Therefore,

4+4

4×4

=2Ω

Similarly,

12+6

12×6

=4Ω

Now,

2ω,4Ω,1Ω are connected in series,

So,

1+2+4=7Ω

ii)The current in each resistor is:

I=

R+r

E

=

7+1

16

=2A

Now, Let us consider the resistor between C and D are the parallel combination of two resistences,

So, the current should be divided in the reverse ratio of the resistance,

if I

1

is the current through 12Ω and I

2

is the current through 6Ω then,

I

2

T

1

=

12

6

=

2

1

So, the current through 12Ω and 6Ω is

3

2

Aand

3

4

A

iii) The voltage V

AB

in between A and B is the product of the total current between A and B and the equivalent resistance between A and B,

Therefore,

V

AB

=2×2=4v

Voltage drop across V

BC

=2×1=2V

Voltage across V

CD

=2×4=8V

Answer 2

Yes why not I will help