Question

any math expert here can answer?​

Answer 1

Answer:

hope it's help you

Step-by-step explanation:

Answer 2

Answer:

Given,

    $[([\frac{1}{7^2}]^-^2)^-^\frac{1}{3} ]^\frac{1}{4} =7^m$

We know that,

    $(a^m)^n=a^m^*^n$

We can use it here,

∴  $[\frac{1}{7^2}]^-^2^*^-^\frac{1}{3} ^*^\frac{1}{4} =7^m$

    $[7]^-^2}^*^\frac{1}{3} ^*^\frac{1}{2} =7^m$

    $[7]^-^\frac{1}{3} =7^m$

 ∴ $m=-\frac{1}{3}$

                      Hope it helps you ^_^