Question

any math expert please answer​

Answer 1

Answer:

sinx is the fourth derivative

Step-by-step explanation:

$y1 = \frac{d}{dx} ( sinx) \\ y1 = cosx \\ y2 = \frac{d}{dx} ( cosx) \\ y2 = - sinx \\ y3 = \frac{d}{dx} ( - sinx) \\ y3 = - cosx \\ y4 = \frac{d}{dx} ( - cosx) \\ y4 = sinx$

Answer 2

sinx is the fourth derivative-:

\begin{gathered}y1 = \frac{d}{dx} ( sinx) \\ y1 = cosx \\ y2 = \frac{d}{dx} ( cosx) \\ y2 = - sinx \\ y3 = \frac{d}{dx} ( - sinx) \\ y3 = - cosx \\ y4 = \frac{d}{dx} ( - cosx) \\ y4 = sinx\end{gathered}

y1=

dx

d

(sinx)

y1=cosx

y2=

dx

d

(cosx)

y2=−sinx

y3=

dx

d

(−sinx)

y3=−cosx

y4=

dx

d

(−cosx)

y4=sinx