Math, asked by abcd1221, 1 year ago

Any math teacher or expert ? Answer my question plsss ... I will mark answer as brainliest ... I am asking this question second time

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Answered by siddhartharao77
11

Answer:

1 : 8 : 16

Step-by-step explanation:

Given that the diameter of three concentric circles = 1:3:5.

Let the diameter of three concentric circles be x,3x and 5x.

Therefore, radii of three circles are (x/2), (3x/2), (5x/2) (or) x, 3x and 5x.

(i)

Area of innermost region,A₁ = Area of innermost circle = πx².

(ii)

Area of middle circle,A₂ = Area of middle circle - Area of innermost circle

                                        = π(3x)² - πx²

                                        = 9πx² - πx²

                                        = 8πx²


(iii)

Area of Outer region, A₃ = Area of outer circle - Area of middle circle

                                         = π(5x)² - π(3x)²

                                         = 25πx² - 9πx²

                                         = 16πx²


∴Required ratio of the area of three regions = A₁:A₂:A₃

                                                                         = πx² : 8πx² : 16πx²

                                                                         = 1 : 8 : 16.



Hope it helps!


abcd1221: Good tried
abcd1221: But answer is 1:8:16
abcd1221: u did right but just small calculation mistake , 25 - 9 = 16, so edit it , I'll mark as brainliest
siddhartharao77: i have edited..Thanks!
Answered by Juhi200
3

Given that the diameter of three concentric circles = 1:3:5.

Let the diameter of three concentric circles be x,3x and 5x.

Therefore, radii of three circles are (x/2), (3x/2), (5x/2) (or) x, 3x and 5x.

(i)

Area of innermost region,A₁ = Area of innermost circle = πx².

(ii)

Area of middle circle,A₂ = Area of middle circle - Area of innermost circle

                                        = π(3x)² - πx²

                                        = 9πx² - πx²

                                        = 8πx²

(iii)

Area of Outer region, A₃ = Area of outer circle - Area of middle circle

                                         = π(5x)² - π(3x)²

                                         = 25πx² - 9πx²

                                         = 16πx²

∴Required ratio of the area of three regions = A₁:A₂:A₃

                                                                         = πx² : 8πx² : 16πx²

                                                                         = 1 : 8 : 16.

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