Any mathematical way to solve this question other than counting.
Attachments:
Answers
Answered by
0
Yeas there is an easier formula. You can use the formula
x*{1+2+3+....+n+(n+1)} = x*[(n+1)+(n+2)]/2
Where n is the number of vertical lines forming a triangle and x being no of horizontal lines forming a triangle. I can dm you a link for similiar question if you want.
Answered by
0
Answer:
28 is correct answer...
Similar questions