Any mathematical way to solve this question other than counting.
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Yeas there is an easier formula. You can use the formula
x*{1+2+3+....+n+(n+1)} = x*[(n+1)+(n+2)]/2
Where n is the number of vertical lines forming a triangle and x being no of horizontal lines forming a triangle. I can dm you a link for similiar question if you want.
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Answer:
28 is correct answer...
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