Question

Any maths aryabhattas here

Need help in maths plz

Topic:-Suface area and volumes(cube and cuboid)

Need 5 questions in twisted way with solutions plz

Only for maths aryabhatta abd bs and bs

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Answer 1

Find the volume of a wall that is build with 2200 bricks if the dimension of each brick is 10cm 5cm and 2cm.

The capacity of a tank is 24000 litres .If the area of the base of the tank is 8m^2, find its depth.

How many bricks each measuring 28cm long, 12.5 cm wide and 9cm thick will be required to build a wall 16 metres long, 3.5 metres high and 45 cm thick ?

HOPE HELPS :D

Answer 2

Hey there !!

This Question is taken from Class 10th Maths NCERT

Question -

⟶Three metallic solid cubes whose edges are 3vcm , 4cm , 5 cm are melted and formed into a single cube , find the edge of cube so formed ,

solution ⟹

let the length of new cube formed be x cm

then the volume of the new cube = sum of the volumes of three metallic cubes


⟹ x³= 3 ³+ 4.³ + 5 ³

⟹ x³= 27 + 64 + 125

⟹ x³ = 216

⟹ x = 6 cm


Questions 2⟶

Two cubes each of 10cm edge are joined end to end , Find TSA of the resulting cuboid

solution ⟹
If two cubes are joined end to end , we get a cuboid such that -

l = length of the resulting cuboid = 10 + 10 = 20 cm

b = 10cm

h = 10cm

TSA of the cuboid = 2 ( lb + bh + hl )

⟹ 2 ( 20 × 10 + 10 × 10 + 20 × 10 ) cm²

⟹ 1000 cm²


Question - 3 ⟹
three cubes whose edges measure 3 cm 4 cm and 5 cm respectively to form a single cube find its is also find the surface area of the new cube

solution ⟹
let X be the age of the new cube then

volume of the new cube is = to sum of the new volumes of 3 Cube
⟹ x ³ = 3³ + 4³ + 5³ = 27 + 64 + 125

x ³ = 216 = 6 cm

surface area of the new cube = 6x² = 6 × 6² = 216 cm²


Questions -4
three cubes each of side 5 cm are joined end to end find the surface area of the resulting cuboid


Solution -
let l be the length b be the breadth and h be the height of the cuboid

then given that -
l = 15 cm , b = 5 cm , h , = 5 cm

SA of the cuboid = 2 ( 15 × 5 + 5 ×5 + 15×5 ) cm ²

= 2 ( 75 + 25 + 75 ) cm²

= 350 cm²


Question - 5
the dimensions of metallic cuboid are 100 cm by 80 CM by 64 cm It is melted and recast into a cube find the surface area of the cube

solution -
did the length of each edge of recasted cube be a cm

volume of the metallic cuboid = 100 × 80 × 64 = 512000 cm³

so , Volume of cube = Volume of cuboid

=> a³ = 512× 1000

=> a ³= 512× 1000

=> a ³. = [8 × 10]³

=> a = 80 cm

SA of the cube = 6 a²

= 6( 80)² = 38400 cm²


Hope this all 5 Questions Would help u !!