any maths expert here pls help me out pls answer if u know pls no spamming pls
excluding q.no.3
Answers
Answer:
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Step-by-step explanation:
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Q.2]
a) (9+4) X 1/8
= 13 X 1/8
= 13/8
b) ((2/3)^7)^5 X 2/3^-35
= using (a^n)^m = a^nm
= 2/3^35 X 2/3^-35
= using a^n X a^m = a^n+m
= 2/3^35+(-35)
=2/3^ 35-35
= 2/3^0
using a^0 = 1
Therefore, 2/3^0 = 1
Q.3] Excluded by you
Q.4]5(x-2)+4(x-3)+5(x-4)
= 5x - 10 + 4x - 12 + 5x - 20
= 5x +4x +5x -10 -12 -20
= 14x -42
Q.5](7x-2y)^2
= using (a-b)^2 = 2 - 2ab + b^2
= (7x)^2 - 2 X 7x X 2y+ (2y)^2
= 49x^2 - 28xy + 4y^2
Q.6](103)^3
= 103^3 = (100 + 3)^3
= using (a+b)^3 = a^3 + 3a^2b + 3ab^2 + b^3
= 100^3 + 3 X 100^2 X 3 + 3 X 100 X 3^2 + 3^3
= 1000000 + 9 X 10000 + 300 X 9 + 27
= 1000000 + 90000 + 2700 + 27
= 1090000 + 2727
= 1092727
Q.7]
= (6a^2 - 7a - 5) ÷ (2a-1)
after dividing, quetioent = 3a - 2 and remainder = -7.
Division photo is attached find it.
Q.8]
Area = x^2 + 9x + 18
Breadth = x + 6
Length = ?
Let length = L
Area of rectangle = L X B
Therefore,
x^2 + 9x + 18 = (x+6) X L
and,
L = ( x^2 + 9x + 18) / (x+6)
Division photo is uploaded please find it.
Therefore, length = (x+3) units
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Given : one number of Pythagorean triplet is 6
To find : Pythagorean triplet
Solution:
Pythagorean triplet
2m , m² - 1 & m² + 1
6 = 2m
=> m = 3
m² - 1 = 3² - 1 =8
m² - 1 = 3² + 1 = 10
6 , 8 & 10 are Pythagorean triplet
5(x - 2) + 4(x - 3) + 5(x - 4)
= 5x - 10 + 4x - 12 + 5x - 4
= 14x - 26
(7x - 2y)²
using (a - b)² = a² -2ab + b²
a = 7x
b = 2y
= 49x² - 28xy + 4y²
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