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Answered by
6
ANSWER:------
328... {B
329...{A
330...{B
331...{C
332...{B
hope it helps:--
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Answered by
42
Hi friend here is your answer
______________________________________
328) The person with blood group A posses antigen A and antibody B
329) The cross gives the F1 generation as AaBbCc
Then we know that the gametes are given by the formula
Where n stands for heterozygous
330) It will be Genotypically Aa and phenotypically A
331)
332) There will be four type of gametes as follows
TR, Tr, tR and tr
______________________________________
328) The person with blood group A posses antigen A and antibody B
329) The cross gives the F1 generation as AaBbCc
Then we know that the gametes are given by the formula
Where n stands for heterozygous
330) It will be Genotypically Aa and phenotypically A
331)
332) There will be four type of gametes as follows
TR, Tr, tR and tr
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