Question

any number has square then 4 twice 12 more .find number.

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Answer 1

Step-by-step explanation:

let the number is x .

${x}^{2} = 4x + 12 \: \: \: \: \: \: \: \: \: \: (given) \\ {x}^{2} - 4x - 12 = 0 \\ {x}^{2} - 6x + 2x - 12 = 0 \\ x(x - 6) + 2(x - 6) = 0 \\ (x - 6)(x + 2) = 0 \\ x - 6 = 0 \: \: \: or \: \: \: x + 2 = 0 \\ x = 6 \: \: \: \: \: or \: \: \: \: \: \: x = - 2 < 0 \\ x = 6$

Answer 2

Answer:

the number is 6

Step-by-step explanation:

let the number be x

$x^{2} =4x+12\\x^{2} -4x=12\\x^{2} -4x-12=0\\x^{2} +2x-6x-12=0\\x(x+2)-6(x+2)=0\\(x-6)(x+2)=0\\x=6,-2$