Question

any object of height 2 centimetre is placed perpendicular to principal axis of concave lens of focal length 12 centimetre then find the height of the image of the object is placed at 8 cm from the lens​

Answer 1

height of object, h = 2cm

focal length of concave lens, f = -12cm

object distance from the lens, u = -8cm

using lens maker formula,

1/v - 1/u = 1/f

or, 1/v - 1/-8 = 1/-12

or, 1/v = 1/-12 + 1/-8

or, 1/v = -(8 + 12)/96

or, 1/v = -20/96

or, v = -4.8cm

hence, image distance from lens, v = -4.8cm

now magnification for lens, m = v/u

or, height of image/height of object = v/u

or, height of image/2cm = (-4.8cm)/(-8cm)

or, height of image = 1.2cm

hence, image is virtual, diminished. and height of image is 1.2cm

Answer 2

Explanation:

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