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IF MOMENTUM OF A BODY INCREASES BY 50 PERCENT IT'S KINETIC ENERGY WILL INCREASE BY 50 PERCENT
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K.E=1/2mv²=(mv)²/2m
P=mv
⇒K.E=P²/2m
K.E1/K.E2=P1²/P2²
P2=(3/2)P1
K.E2/K.E1=9/4
K.E2/K.E1 x100=9/4x100=225
The increase in % is 225-100 = 125%
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