Question

Any one can give me ch 8 motion class 9 science(NCRET)textual question?? In the written form​

Answer 1

Answer:

• Answer:
• 90 km/hr fast must the car travel for the next 50 km
• Explanation:
• Given that,
• Total distance = 100 km
• First distanced_{1} = 50\ kmd
• 1
• =50 km
• Speedv_{1} = 30\ km/h^{-1}v
• 1
• =30 km/h
• −1
• The car travels 50 km with speed 30 km/hr.
• The time taken is
• t=\dfrac{d}{v}t=
• v
• d
• t_{1}=\dfrac{50}{30}t
• 1
• =
• 30
• 50
• t_{1}= 1.67\ hrt
• 1
• =1.67 hr
• Let us consider, the car travels next 50 km with speed v₂ km/hr.
• The time taken is
• t_{2}= \dfrac{50}{v_{2}}t
• 2
• =
• v
• 2
• 50
• The average speed v_{avg}=\dfrac{D}{T}v
• avg
• =
• T
• D
• Here, D = total distance
• T= total time
• The average speed is
• 45=\dfrac{100}{\dfrac{5}{3}+\dfrac{50}{v_{2}}}45=
• 3
• 5
• +
• v
• 2
• 50
• 100
• v_{2}=90\ km/hrv
• 2
• =90 km/hr
• Hence, 90 km/hr fast must the car travel for the next 50 km.

Explanation:

• please make it a brainliest answer.