Question

any one can say the correct answer for this question​

Answer 1

1 ) x² + 5x - 6 = 0

this eq. not a solve able

2) x² + 6x + 8 = 0

x² + 4x + 2x + 8 = 0

x(x + 4) + 2(x + 4) = 0

(x + 2)(x + 4)

3) x² + 3x + 2 = 0

x² + x + 2x + 2 = 0

x(x + 1) + 2(x + 1) = 0

(x + 2)(x + 1)

4) 3x² + 18x² - 21x

divide the eq. by 3x we get

x² + 6x - 7 = 0

x² + 7x - x - 7 = 0

x(x + 7) - (x + 7) = 0

(x - 1)(x + 7)

5) 2x³ + 14x² + 24x = 0

divide the eq. by 2x we get

x² + 7x + 12 = 0

x² + 4x + 3x + 12 = 0

x(x + 4) + 3(x + 4) = 0

(x + 4)(x + 3)

Answer 2

Step-by-step explanation:

(1)X²+5X-6=X²+6X-X-6=X(X+6)-1(X+6)=(X+6)(X-1)

(2)X²+6X+8=X²+4X+2X+8=X(X+4)+2(X+4)=(X+4)(X+2)

(3)X²+3X+2=X²+2X+X+2=X(X+2)+1(X+2)=(X+2)(X+1)

(4)3X³+18X²-21X=X(3X²+18X-21)=X(3X²+21X-3X-21)=X{3X(X+7)-3(X+7)}=X(X+7)(X-3)

(5)2X³+14X²+24X=X(2X²+14X+24)=X(2X²+8X+6X+24)=X{2X(X+4)+6(X+4)}=X(X+4)(2X+6)

HOPE IT WILL HELP YOU!!!