Question

any one can solve it......

Answer 1

$the \: sum \: of \: odd \: power \: coeffients \: is \: equal \: to \: the \: sum \: of \: even \: power \: coefficints \: then \: (x + 1) \: is \: a \: factor \: of \: expression \\ 1 - 7 = 0 - 6 \\ - 6 = - 6 \\ so \: (x + 1)is \: a \: factor \: of \: ( {x}^{3} - 7x - 6) \\ (x + 1)( {x}^{2} - x - 6) \\ (x + 1)( {x}^{2} - 3x + 2x - 6) \\ (x + 1)(x(x - 3) + 2(x - 3)) \\ (x + 1)(x - 3)(x + 2)$