any one can solve it
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Sum of first two terms of a G. P. = - 4
Fifth term of the G. P. = ar^4
Third term of the G. P. = ar^2
According to the question,
ar^4 = 4 × ar^2
ar^4 / ar^2 = 4
r^2 = 4
r = 2
Common Ratio, r = 2
Sum of first two terms,
= a (r^n - 1 ) / ( r- 1 ) = - 4
=> a ( 2^2 - 1 ) / ( 2 - 1 ) = - 4
=> a ( 3 ) = - 4
=> a = - 4 / 3
First term, a = - 4/ 3
G. P. = a, ar, ar^2.....
G.P. = - 4 / 3 , - 8 /3, - 16 / 3........
Fifth term of the G. P. = ar^4
Third term of the G. P. = ar^2
According to the question,
ar^4 = 4 × ar^2
ar^4 / ar^2 = 4
r^2 = 4
r = 2
Common Ratio, r = 2
Sum of first two terms,
= a (r^n - 1 ) / ( r- 1 ) = - 4
=> a ( 2^2 - 1 ) / ( 2 - 1 ) = - 4
=> a ( 3 ) = - 4
=> a = - 4 / 3
First term, a = - 4/ 3
G. P. = a, ar, ar^2.....
G.P. = - 4 / 3 , - 8 /3, - 16 / 3........
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