Question

any one can solve this

Answer 1

I solved the first term
${ (\frac{ {x}^{a} }{ {x}^{b} } ) }^{ {a}^{2} + 2ab + {b}^{2} }$
${x}^{(a - b)( {a}^{2} + 2ab + {b}^{2} )}$
x
${x}^{ {a}^{3} - {b}^{3} }$
by solving the three terms
you get
${x}^{ {a}^{3} - {b}^{3} + {b}^{3} - {c}^{3} + {c}^{3} - {a}^{3} }$
${x}^{0}$
=1
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Answer 2

Proved ho gaya hai please agar koi galti ho to i am sorry