Question

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solve it my ques
























We have writen the real numberof the rootof the equation (x-1)+(x-2)^{2} +(x-3)^{2} =0

Answer 1

Given Equation is (x - 1) + (x - 2)^2 + (x - 3)^2 = 0.

⇒ x - 1 + x^2 + 4 - 4x + x^2 + 9 - 6x = 0 = 0

⇒ 2x^2 - 9x + 12 = 0

We know that equation has real roots if D ≥ 0.

Now,

⇒ D = b^2 - 4ac

        = (-9)^2 - 4(2)(12)

        = 81 - 96

        = -15 < 0 (No any real roots exists)

Therefore, there are no real roots (or) 0 real roots in the given equation.

Hope it helps!