any one give me answer please 3 or 4
Answers
Answer:
4) - :
(X×4) - (-1×1 ) = 13
4x -(-1)= 13
4x+1 = 13
4x = 13 -1
4x = 12
x = 12/4
x = 3
5) - :
(a) substitute y = 5 in equation 2x+3y = 11
2x + 3×5 = 11
2x + 15 = 11
2x = 11 - 15
2x = -4
x = -4/2
x= -2
(b) substitute x = 4 in equation 2x+3y= 11
2×4 +3y = 11
8+3y = 11
3y = 11 - 8
3y = 3
y = 3/3
y = 1
3.(A) - :
S = { A ,B ,E, O, P, T }
n(s) = { 6 }
X = { A, E, O }
n(x) = 3
p(x) = n(x) /n(s) = 3/6 = 1/2
(ii) - :
substitute x = -1 in equation
5× (-1)² + k×-1 - 7 = 0
5× 1 - k - 7 = 0
5-k-7 = 0
-2-k = 0
-k = 2
k = -2
Answer:
Answer:
4) - :
(X×4) - (-1×1 ) = 13
4x -(-1)= 13
4x+1 = 13
4x = 13 -1
4x = 12
x = 12/4
x = 3
5) - :
(a) substitute y = 5 in equation 2x+3y = 11
2x + 3×5 = 11
2x + 15 = 11
2x = 11 - 15
2x = -4
x = -4/2
x= -2
(b) substitute x = 4 in equation 2x+3y= 11
2×4 +3y = 11
8+3y = 11
3y = 11 - 8
3y = 3
y = 3/3
y = 1
3.(A) - :
S = { A ,B ,E, O, P, T }
n(s) = { 6 }
X = { A, E, O }
n(x) = 3
p(x) = n(x) /n(s) = 3/6 = 1/2
(ii) - :
substitute x = -1 in equation
5× (-1)² + k×-1 - 7 = 0
5× 1 - k - 7 = 0
5-k-7 = 0
-2-k = 0
-k = 2
k = -2
Step-by-step explanation:
Hope this answer will help you.✌️