Question

any one please answer my question as quick as possible and please guys don't write alphabets

Answer 1

Answer:

$\frac{ {25}^{n} \times {5}^{3} \times (125 {)}^{3} }{5 \times (625 {)}^{4} } = 125 \\ \\ \frac{ {( {5}^{2} )}^{n} \times {5}^{3} \times({5}^{3} {)}^{3} }{5 \times {(25}^{2} {)}^{4} } = {5}^{3} \\ \\ \frac{ {5}^{2n} \times {5}^{3} \times {5}^{9} }{5 \times ( {5}^{2} {)}^{8} } = 125 \\ \\ \frac{ {5}^{2n + 3 + 9} }{5 \times {5}^{16} } = {5}^{3} \\ \\ \frac{ {5}^{2n + 12} }{ {5}^{17} } = {5}^{3} \\ \\ {5}^{2n + 12} = {5}^{3} \times {5}^{17} \\ {5}^{2n + 12} = {5}^{17 + 3} \\ {5}^{2n + 12 } = {5}^{20} \\ now \: 2n + 12 = 20 \\ 2n = 20 - 12 \\ 2n = 8 \\ n = \frac{8}{2} \\ n = 4$