Question

any one plse explain this ..how sec thetta and cot theta changed to next stp​

Answer 1

Answer:

$\sec(x) = \frac{1}{ \cos(x) } \\ \cot(x) = \frac{ \cos(x) }{ \sin(x) } \\ \\ so \: \frac{b}{a} \sec(x) \times \cot(x) \\ = \frac{b \cos(x) }{a \cos(x) \times \sin(x) }$

hope it helps

Answer 2

Here,

$= = > \: \: \sec \: \theta = \frac{1}{ \cos \: \theta }$

and,

$= = > \: \: \cot \: \theta = \frac{ \cos \: \theta }{ \sin \: \theta}$

In the next, we substitute the values for sec θ and cot θ, respectively.