any one solve question no. 2
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let first no be x
second be 3x
cube of first no = x.x.x=x^3
cube of second no=3x.3x.3x=27x^3
cube of second no=27 cube of first no.
second be 3x
cube of first no = x.x.x=x^3
cube of second no=3x.3x.3x=27x^3
cube of second no=27 cube of first no.
Answered by
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⏳hey friend your ans is here :-
let the required no. be x .
then it's cube will be x ^3................(i)
and on making this no. tripple
we would get the no. 3x
and when we would do find cube of 3x that will give us 27 x^3......................(ii).
hence from (i). and (ii). we conclude that :-
if a no. is tripled, then it's cube is 27 times the cube of given no.
hence proved.
hope this ans would help you.
✔so I request you to please mark it as brainliest ans.
{♤♤♡♡ THANK YOU ♤♤♡♡}.
let the required no. be x .
then it's cube will be x ^3................(i)
and on making this no. tripple
we would get the no. 3x
and when we would do find cube of 3x that will give us 27 x^3......................(ii).
hence from (i). and (ii). we conclude that :-
if a no. is tripled, then it's cube is 27 times the cube of given no.
hence proved.
hope this ans would help you.
✔so I request you to please mark it as brainliest ans.
{♤♤♡♡ THANK YOU ♤♤♡♡}.
Anonymous:
please mark as brainliest
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