Math, asked by prashant247, 4 months ago

ANY ONE SOLVE THis????

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..first time i have to ask math que​

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Answered by Anonymous
12

Answer:

Hello❤️

This problem is from trigonometry. So there are different formulas for sin,cos,tan etc.

Like for sin(x) if measured in radians is equals to sin(x)= x-x^3/3!-x^5/5!…..

So now sin(x)/x= 1-x^2/6-x^3/120…..

If x is small, we get, sin(x)/x = 1-x^2/6

Now if we compare the values of sin(x)/x as given in the question and derived by us, we get

==> 1-x^2/6 = 2165/2166

==> 1–2165/2166 =x^2/6 (taking the l.c.m and taking 2165/2166 from right to left so it changes its sign from + to - and x^2/6 changes sign from - to + )

==> 1/2166 = x^2/6

==> x^2 = 6/2166 (cross multiplication)

==> x^2 = 361

==> x= +- 19 (taking square root both the sides)

So we get value of x as +19 and -19.

Let me know if this was helpful or not. :)

Answered by hassanalihassanali06
3

Answer:

Parashant you don't understand my talking... I am saying ,that Can I thanks your answers ......?

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