Question

any one tell its about of class 7​

Answer 1

$\Large{\underline{\bf{Given:}}}$

☞ PQR is a Right Angled Triangle

☞ ∠RPQ = 90° & ∠PQR = 35°

☞ ∠PRQ = x°

$\Large{\underline{\bf{To\;Find:}}}$

☞ The Value of 'x'

$\huge{\underline{\underline{\bf{Solution:}}}}$

W.K.T

✯ Sum of Angles in a Triangle is 180°

So, ∠RPQ+∠PQR+∠PRQ = 180°

$→\;{\sf{90°+35°+x° = 180°}}$

$→\;{\sf{125°+x° = 180°}}$

$→\;{\sf{x° = 180°-125°}}$

$➝\;{\bf{x° = 55°}}$

$\Large{\green{\underline{\underline{\tt{AnSweR:}}}}}$

Value of x (∠PRQ) ◕➜ $\huge{\red{\mathfrak{55°}}}$

Hope It Helps You ✌️