Question

any physics expert here
plz help me​

Answer 1

V = (80 + j 60) = 100 ∠ 36.9°;

I = − 4 + j 10 = 10.77 ∠ tan−1 (− 2.5)

= 10.77 ∠ (180° − 68.2°)

= 10.77 ∠ 111.8°

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(i) Z = V/I = 100 ∠36.9°/10.77∠ 111.8°

= 9.28 ∠ − 74.9° = 9.28 (cos 74.9° − j sin 74.9°)

= 2.42 − j 8.96 Ω

Hence R = 2.42 Ω and XC = 8.96 Ω capacitive

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(ii) P = I² R = 10.772 × 2.42 = 2.81 W

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(iii) Phase angle between voltage and current = 74.9° with current leading as shown in Fig.

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I HOPE IT HELPS .