Any positive ood integer is of the form 6 q+1, or if 6q + 3 or 6q +5, where q is some integer
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Hello Dear!!!
Here's your answer...
By Euclid division lemma...
a = bq+r
Here,
b is 6
And r should be less than 6
r = (1,2,3,4,5,6)
a = bq+r
If r = 0
a = 6q +0
It is even... because it is divisible by 2
If r = 1
a = 6q+1
It is odd... because it is not divisible by 2
If r = 2
a = 6q+2
It is even...it is divisible by 2
If r = 3
a = 6q+3
It is odd... because it is not divisible by 2
If r =4
a = 6q+4
It is even... because it is divisible by 2
If r = 5
a = 6q + 5
It is odd.. because it is not divisible by 2
So...
Any positive odd integer will be in the form of 6q+1 or 6q + 3 or 6q + 5
__________________
Hope this helps you...
Hope you got it...
Here's your answer...
By Euclid division lemma...
a = bq+r
Here,
b is 6
And r should be less than 6
r = (1,2,3,4,5,6)
a = bq+r
If r = 0
a = 6q +0
It is even... because it is divisible by 2
If r = 1
a = 6q+1
It is odd... because it is not divisible by 2
If r = 2
a = 6q+2
It is even...it is divisible by 2
If r = 3
a = 6q+3
It is odd... because it is not divisible by 2
If r =4
a = 6q+4
It is even... because it is divisible by 2
If r = 5
a = 6q + 5
It is odd.. because it is not divisible by 2
So...
Any positive odd integer will be in the form of 6q+1 or 6q + 3 or 6q + 5
__________________
Hope this helps you...
Hope you got it...
harshu44:
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