any small Mercury drops of same size are charged to V volts each if they collagens to form a single drop than its potential will be
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1
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This implies, the capacity of the bigger drop is n1/3 times the capacity of each small drop. Ptential of 1 big drop is given by V=n. So, the potential of the bigger drop is n2/3 times the potential of the smaller drop.
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ok I have give u 13 thanks
ok bye
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