Question

Any solution for this​

Answer 1

Answer:

f(x) = log(x + √1+x²)

f(-x) = log(-x + √1 + x²)

f(-x) = log (√ √1 + x² + x √1 + x² + x - X)

f(-x) = log 1+x²-x² √1 + x² + x

f(-x) = log [VI+XZ+X] 1

f(-x) = -log(√1 + x² + x)

⇒ f(-x) = -f(x)

Hence, f is an odd function.