any two numbers which product is 27 and sum is 13
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2y² + 27 y + 13 =0
2y² + 26 y + y + 13 = 0
2y(y+13) + 1(y+13) = 0
(2y+1) (y+13) = 0
y = -1/2 or -13
2y² + 26 y + y + 13 = 0
2y(y+13) + 1(y+13) = 0
(2y+1) (y+13) = 0
y = -1/2 or -13
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Answered by
1
2y²+27y+13=0
by quadratic formula
where a=2
b=27
c=13
D=b²-4ac
=27²-4×2×13
=729-104
=625
so
x=-b±√D/2a
= -(27)±√625/2×2
= -27±25/4
so
= -27-25/4 and = -27+25/4
= -52/4 = -2/4
so zeroes are -13 and -1/2
I hope this will help you mark me brainliest
by quadratic formula
where a=2
b=27
c=13
D=b²-4ac
=27²-4×2×13
=729-104
=625
so
x=-b±√D/2a
= -(27)±√625/2×2
= -27±25/4
so
= -27-25/4 and = -27+25/4
= -52/4 = -2/4
so zeroes are -13 and -1/2
I hope this will help you mark me brainliest
good alternative method.
yes
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