Question

any which you can answer plss

Answer 1

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2)X/3+1=7/15

X/3=7/15-1

X/3=7-15

_____ ( ON TAKING LCM)

15

X/3=-8/15

X=-8/15×3=-8/5

3) Out of 52 cards, one card can be drawn in 52 ways. So, total number of elementary events = 52 (i) There are four ace cards in a pack of 52 cards. So, one ace can be chosen in 4 ways. Favorable number of elementary events = 4 Hence, required probability =4/52=1/13 (ii) There are 26 red cards in a pack of 52 cards. Out of 26 red cards, one card can be chosen in 26 ways. Favourable number of elementary events= 26 Hence, required probability=26/52=1/ 13

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