anybody answer please for me
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Heya mate,
Here is your answer,. ⬇️⬇️
_________
Here, we have,
Q is the mid point of AE.
So, AQ = QE
Thus, AE = AQ + QE
=> AE = QE + QE = 2 QE
=> QE/AE = 1/2. .............. (1)
And, now, we have,
BA = DC
Again, C is the mid point of DE.
So, DC = CE.
Thus, DE = DC + CE
=> DE = DC + DC = 2 DC
=> DE = 2 BA. [ BA = DC ]
=> BA/DE = 1/2. .............. (2)
Now, from (1) and (2),
BA/DE = 1/2 = QE/AE
=> BA/DE = QE/AE
=> BA * AE = QE * DE. .............(3)
Now, we have that,
P is the mid point of AD.
So, PD = AP. ...........(4)
At last, from (3) and (4),
BA * AE * PD = QE * DE * AP.
➡️ Hence, it is proved that,
BA * AE * PD = QE * DE * AP.
__________
Hope this helps,.
If helps, please mark 'thanks'
__________
REGARDS, ARNAB ✌️
THANK YOU
Here is your answer,. ⬇️⬇️
_________
Here, we have,
Q is the mid point of AE.
So, AQ = QE
Thus, AE = AQ + QE
=> AE = QE + QE = 2 QE
=> QE/AE = 1/2. .............. (1)
And, now, we have,
BA = DC
Again, C is the mid point of DE.
So, DC = CE.
Thus, DE = DC + CE
=> DE = DC + DC = 2 DC
=> DE = 2 BA. [ BA = DC ]
=> BA/DE = 1/2. .............. (2)
Now, from (1) and (2),
BA/DE = 1/2 = QE/AE
=> BA/DE = QE/AE
=> BA * AE = QE * DE. .............(3)
Now, we have that,
P is the mid point of AD.
So, PD = AP. ...........(4)
At last, from (3) and (4),
BA * AE * PD = QE * DE * AP.
➡️ Hence, it is proved that,
BA * AE * PD = QE * DE * AP.
__________
Hope this helps,.
If helps, please mark 'thanks'
__________
REGARDS, ARNAB ✌️
THANK YOU
shiny209:
thanks man how u guys solve such diffficult problems
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