Question

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Answer 1

Answer:

Given

PR=4

RL=6

AC=8

In ΔPLR and ΔABC

∠PRL=∠ACB (right angles)

∠LPR=∠BAC ( Angles made by sunlight on top are congruent)

By AA test of similarity

ΔPLR∼ΔABC

∴

AC

PR

=

BC

LR

(Corresponding sides are proportional)

⇒

8

4

=

x

6

⇒x=12

Hence, the length of shadow of bigger pole due to sunlight is 12 m .

Step-by-step explanation:

Correct answer

Answer 2

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°°° Solution °°°

Given

PR = 4

RL = 6

AC = 8

In ΔPLR and ΔABC

∠PRL=∠ACB (right angles)

∠LPR=∠BAC ( Angles made by sunlight on top are congruent)

By AA test of similarity

ΔPLR∼ΔABC

∴ ACPR = BCLR

(Corresponding sides are proportional)

⇒ 84 = x 6

⇒x=12

Hence, the length of shadow of bigger pole due to sunlight is 12 m .