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Diameter=10m
So,radius=half of the diameter
=5m
height=14m
therefore, volume of the well=volume of the earth dug
So, volume=πr^2h
=22/7×5×5×14
=22×5×5×7
=22×25×7
=3,850m^2
therefore,area=π×[(R1×R2)]
therefore,R1=5
and R2=5+5=10
=22/7×[(5+10)]
=22/7×[(5)+(15)]
So,find the area and then height of the embankment=V/A
Hope this helps..
So,radius=half of the diameter
=5m
height=14m
therefore, volume of the well=volume of the earth dug
So, volume=πr^2h
=22/7×5×5×14
=22×5×5×7
=22×25×7
=3,850m^2
therefore,area=π×[(R1×R2)]
therefore,R1=5
and R2=5+5=10
=22/7×[(5+10)]
=22/7×[(5)+(15)]
So,find the area and then height of the embankment=V/A
Hope this helps..
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2
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