Question

anybody can solve it??

Answer 1

In the figure, OAPB is the minor arc.

$\text{Arc length =} \frac{ \theta}{360} \times 2\pi r$

$\text{Area of sector =} \frac{ \theta}{360} \times \pi {r}^{2}$


here, angle of the arc at the centre = 60° and radius = 6cm

$\text{Arc length =} \frac{ 60}{360} \times 2\pi \times 6 = 2\pi \: cm$

$\text{Area of sector OAPB =} \frac{60}{360} \times \pi \times {6}^{2} = 6\pi \: {cm}^{2}$

Answer 2

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In the figure, OAPB is the minor arc.

$\text{Arc length =} \frac{ \theta}{360} \times 2\pi r$

$\text{Area of sector =} \frac{ \theta}{360} \times \pi {r}^{2}$

here, angle of the arc at the centre = 60° and radius = 6cm

$\text{Arc length =} \frac{ 60}{360} \times 2\pi \times 6 = 2\pi \: cm$

$\text{Area of sector OAPB =} \frac{60}{360} \times \pi \times {6}^{2} = 6\pi \: {cm}^{2}$

HOPE SO IT WILL HELP......